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6x^2=144-12x
We move all terms to the left:
6x^2-(144-12x)=0
We add all the numbers together, and all the variables
6x^2-(-12x+144)=0
We get rid of parentheses
6x^2+12x-144=0
a = 6; b = 12; c = -144;
Δ = b2-4ac
Δ = 122-4·6·(-144)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-60}{2*6}=\frac{-72}{12} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+60}{2*6}=\frac{48}{12} =4 $
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